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-rwxr-xr-xindra/lib/python/indra/util/llmanifest.py82
1 files changed, 75 insertions, 7 deletions
diff --git a/indra/lib/python/indra/util/llmanifest.py b/indra/lib/python/indra/util/llmanifest.py
index d4e61aedd1..7050ce43b7 100755
--- a/indra/lib/python/indra/util/llmanifest.py
+++ b/indra/lib/python/indra/util/llmanifest.py
@@ -376,12 +376,30 @@ class LLManifest(object):
self.excludes.append(glob)
def prefix(self, src='', build=None, dst=None):
- """ Pushes a prefix onto the stack. Until end_prefix is
- called, all relevant method calls (esp. to path()) will prefix
- paths with the entire prefix stack. Source and destination
- prefixes can be different, though if only one is provided they
- are both equal. To specify a no-op, use an empty string, not
- None."""
+ """
+ Usage:
+
+ with self.prefix(...args as described...):
+ self.path(...)
+
+ For the duration of the 'with' block, pushes a prefix onto the stack.
+ Within that block, all relevant method calls (esp. to path()) will
+ prefix paths with the entire prefix stack. Source and destination
+ prefixes can be different, though if only one is provided they are
+ both equal. To specify a no-op, use an empty string, not None.
+
+ Also supports the older (pre-Python-2.5) syntax:
+
+ if self.prefix(...args as described...):
+ self.path(...)
+ self.end_prefix(...)
+
+ Before the arrival of the 'with' statement, one was required to code
+ self.prefix() and self.end_prefix() in matching pairs to push and to
+ pop the prefix stacks, respectively. The older prefix() method
+ returned True specifically so that the caller could indent the
+ relevant block of code with 'if', just for aesthetic purposes.
+ """
if dst is None:
dst = src
if build is None:
@@ -390,7 +408,57 @@ class LLManifest(object):
self.artwork_prefix.append(src)
self.build_prefix.append(build)
self.dst_prefix.append(dst)
- return True # so that you can wrap it in an if to get indentation
+
+ # The above code is unchanged from the original implementation. What's
+ # new is the return value. We're going to return an instance of
+ # PrefixManager that binds this LLManifest instance and Does The Right
+ # Thing on exit.
+ return self.PrefixManager(self)
+
+ class PrefixManager(object):
+ def __init__(self, manifest):
+ self.manifest = manifest
+ # stack attributes we manage in this LLManifest (sub)class
+ # instance
+ stacks = ("src_prefix", "artwork_prefix", "build_prefix", "dst_prefix")
+ # If the caller wrote:
+ # with self.prefix(...):
+ # as intended, then bind the state of each prefix stack as it was
+ # just BEFORE the call to prefix(). Since prefix() appended an
+ # entry to each prefix stack, capture len()-1.
+ self.prevlen = { stack: len(getattr(self.manifest, stack)) - 1
+ for stack in stacks }
+
+ def __nonzero__(self):
+ # If the caller wrote:
+ # if self.prefix(...):
+ # then a value of this class had better evaluate as 'True'.
+ return True
+
+ def __enter__(self):
+ # nobody uses 'with self.prefix(...) as variable:'
+ return None
+
+ def __exit__(self, type, value, traceback):
+ # First, if the 'with' block raised an exception, just propagate.
+ # Do NOT swallow it.
+ if type is not None:
+ return False
+
+ # Okay, 'with' block completed successfully. Restore previous
+ # state of each of the prefix stacks in self.stacks.
+ # Note that we do NOT simply call pop() on them as end_prefix()
+ # does. This is to cope with the possibility that the coder
+ # changed 'if self.prefix(...):' to 'with self.prefix(...):' yet
+ # forgot to remove the self.end_prefix(...) call at the bottom of
+ # the block. In that case, calling pop() again would be Bad! But
+ # if we restore the length of each stack to what it was before the
+ # current prefix() block, it doesn't matter whether end_prefix()
+ # was called or not.
+ for stack, prevlen in self.prevlen.items():
+ # find the attribute in 'self.manifest' named by 'stack', and
+ # truncate that list back to 'prevlen'
+ del getattr(self.manifest, stack)[prevlen:]
def end_prefix(self, descr=None):
"""Pops a prefix off the stack. If given an argument, checks